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unsigned char用法 在 [問題] printf 和unsigned char* - 看板C_and_CPP - 批踢踢實業坊 的必吃
開發平台(Platform): (Ex: VC++, GCC, Linux, ...)
GCC Linux SUSE
問題(Question)：
最近在寫C，碰到大量的unsigned char*，然後又得認命的去看內容兼找錯，
只好利用printf來把內容顯示出來看，不過在一連串意外之後，
我對printf越來越陌生了 Q口Q
先直接看下面的測試程式：
int int01 = 100;
unsigned char *str;
unsigned char *tmp;
str = (unsigned char *)malloc(1);
tmp = (unsigned char *)malloc(2);
sprintf(str,"%d",int01); //將int01的數值利用sprintf餵給str
memcpy(tmp,str,1); //利用memcpy把數值copy給tmp
printf("%d\n",*str); //輸出 49 (神奇的49....不知道哪來的)
printf("%u\n",*str); //輸出 49 (unsigned dec和樓上吻合)
printf("%x\n",*tmp); //輸出 31 (16進位和樓上吻合)
printf("%x\n",*(tmp+1) ); //輸出 0 (第二個byte沒有數值 正確)
想請問大大，要怎麼餵數值給unsigned char*？
輸出49真的讓我有點傻眼，為什麼不是100 >"<
再請問大大，如果我要在unsigned char *str 當中餵入100的二進位(0x1100100)
然後用printf() 顯示出100的話，我該怎麼改？
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